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Similarly, querying previousSibling on the first child node of the <ul> returns null, too: var myUL = document. childNodes[1]. childNodes[1]. childNodes[1]. childNodes[3]; myUL.childNodes[0].previousSibling; // null Now then, is there a simpler way to query the last child node of the <ul> than keying in childNodes[myUL.childNodes.length - 1] Oh, you betcha. Just query the aptly named lastChild member: var myUL = document. childNodes[1]. childNodes[1]. childNodes[1]. childNodes[3]; myUL.lastChild.previousSibling; // <li id="linkedin" class="sprite"> Conversely, every kind of node has a firstChild member referring to its first child node. So rather than querying childNodes[0], you can save a few keystrokes with firstChild. Note that, in addition to saving keystrokes, lastChild and firstChild read better than their childNodes equivalents. So, click Clear in both Firebug panels and give firstChild a try, verifying this and the previous sample with Figure 7 7: var myUL = document. childNodes[1]. childNodes[1]. childNodes[1]. childNodes[3]; myUL.firstChild.nextSibling; // <li id="twitter" class="sprite">

Finally, we return 0 and thus end main():

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Much like the = and operators, the greater than and less than operators always return a result as a Boolean. This means the result of using an operator can be either true or false. To use these operators, you need to understand how a certain character is considered to be greater than another. In MacRoman text, one character is considered less than or greater than another character depending on whether the first character appears before or after the second one in the MacRoman character table (though don t forget that text comparisons may also be affected by ignoring clauses, of course). Refer to Table 3-1 for the order of characters in the MacRoman table. To determine in a script whether one string comes before another string, use the less than operator, which can be written in any of several ways: "a" comes before "b" "a" < "b" "a" is less than "b" Similarly, the greater than operator checks whether the first parameter is greater than the second or appears later in the sorting chain: "a" comes after "b" "a" > "b" "a" is greater than "b" Use the greater than or equal operator to see whether one value is either the same as or greater than another: "a" "b" You can also write this as follows: "a" is greater than or equal to "b" And you can use the less than or equal operator to see whether one value is the same as or less than the other: "a" "b" "a" is less than or equal to "b"

return 0; }

In the spirit of putting characters in order, let s try to analyze a script that sorts a list of strings. First, Script 3-3 shows the script. Note that this script snippet is a prime candidate for a subroutine. The parameter will be the list you want to sort, and the returned result will be the sorted list. For now, though, you will just concentrate on the code itself and not on how it may fit in a script. (I should also note that I did not write this script. This subroutine is a standard beginner sorting example that has been around for decades.) Script 3-3. set theList to {"Dell", "Apple", "HP"} repeat (length of theList) times repeat with j from 1 to (length of theList) 1 if item j of theList > item (j + 1) of theList then set {item j of theList, item (j + 1) of theList} to {item (j + 1) of theList, item j of theList}

Take a look at the definition of PrintDVDTitle() s second parameter. Notice that the first of the two dimensions is missing (the first pair of brackets is empty). While we could have included the first dimension (kMaxDVDs), the fact that we were able to leave it out makes a really interesting point. When memory is allocated for an array, it is allocated as one big block. To access a specific element of the array, the compiler uses the dimensions of the array, as well as the specific element requested to calculate an offset into this block.

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